A department store has average daily sales of \( \$ 29,876.76 \). The standard deviation of sales is \( \$ 1000 \). On Tuesday, the store sold \( \$ 34,893.71 \) worth of goods. Find Tuesday's \( z \) score. (1 point) 5.27 5.33 4.01 5.02

To find Tuesday's \( z \) score, we can use the formula for the \( z \) score: \[ z = \frac{(X - \mu)}{\sigma} \] where \( X \) is the value in question, \( \mu \) is the mean (average), and \( \sigma \) is the standard deviation. Given: - \( X = 34,893.71 \) - \( \mu = 29,876.76 \) - \( \sigma = 1000 \) Now, plug in the values: \[ z = \frac{(34,893.71 - 29,876.76)}{1000} \] Calculating the numerator: \[ 34,893.71 - 29,876.76 = 5,016.95 \] Now, substitute back into the equation: \[ z = \frac{5,016.95}{1000} = 5.017 \] Rounding to two decimal places, we find: \[ z \approx 5.02 \] So, the correct answer is 5.02. Would you like to know more about how \( z \) scores are used in different contexts?