Pregunta
upstudy study bank question image url

up 1 SA papers - Search IEB Mathematics Past Papers |: Mathematics google classroom - Search tps://classroom.google.com/c/NzQ1Mzg3NzMzMjg5 AL MATHEMATICS-Present Value.pptx Open with EXAMPLE Mandy takes out a ten-year loan of R80 000. She repays the loan by means of equal monthly payments starting four months after the granting of the loan. The interest rate is \( 12 \% \) per annum compounded monthly. Calculate the monthly payments. CHECK FOR RagernwTANoHNG

Ask by George Vaughan. in South Africa
Mar 19,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

Mandy's monthly loan payment is approximately R1,168.39.

Solución

To calculate the monthly payments for Mandy's loan, we can use the formula for calculating the present value of an annuity. Given: - Loan amount: R80,000 - Interest rate: 12% per annum compounded monthly - Loan duration: 10 years - Repayment starts 4 months after the loan is granted First, we need to calculate the monthly interest rate: \[ \text{Monthly interest rate} = \frac{12\%}{12} = 1\% \] Next, we can use the formula for the present value of an annuity to calculate the monthly payment: \[ \text{Monthly payment} = \frac{\text{Loan amount} \times \text{Monthly interest rate}}{1 - (1 + \text{Monthly interest rate})^{-\text{Number of payments}}} \] Where: - Number of payments = 10 years * 12 months/year - 4 months = 116 months Let's calculate the monthly payment using the formula. Calculate the value by following steps: - step0: Calculate: \(\frac{\left(80000\times 0.01\right)}{\left(1-\left(1+0.01\right)^{-116}\right)}\) - step1: Remove the parentheses: \(\frac{80000\times 0.01}{1-\left(1+0.01\right)^{-116}}\) - step2: Add the numbers: \(\frac{80000\times 0.01}{1-1.01^{-116}}\) - step3: Convert the expressions: \(\frac{80000\times 0.01}{1-\left(\frac{101}{100}\right)^{-116}}\) - step4: Multiply the numbers: \(\frac{800}{1-\left(\frac{101}{100}\right)^{-116}}\) - step5: Subtract the numbers: \(\frac{800}{\frac{101^{116}-100^{116}}{101^{116}}}\) - step6: Multiply by the reciprocal: \(800\times \frac{101^{116}}{101^{116}-100^{116}}\) - step7: Multiply: \(\frac{800\times 101^{116}}{101^{116}-100^{116}}\) The monthly payment for Mandy's loan is approximately R1,168.39.

Respondido por UpStudy AI y revisado por un tutor profesional

error msg
Explicar
Simplifique esta solución

Extra Insights

To calculate Mandy's monthly payments, we can use the formula for an amortizing loan payment, which is given by: \[ M = P \frac{r(1 + r)^n}{(1 + r)^n - 1} \] Where: - \( M \) is the monthly payment, - \( P \) is the principal amount (R80,000), - \( r \) is the monthly interest rate (annual rate divided by 12), - \( n \) is the total number of payments (in months). In Mandy's case, her monthly interest rate is \( \frac{12\%}{12} = 1\% = 0.01 \), and the total payments over ten years would be \( 10 \times 12 = 120 \) months. Plugging in these values will help you find the answer. Don’t forget to double-check your calculations and ensure you keep track of the monthly compounding nature of the interest to prevent common errors, like mixing up annual and monthly rates!

preguntas relacionadas

Latest Algebra Questions

¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad