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Factor, (If the expression is nonfactorable over the integers, enter NONFACTORABLE.) \[ p^{2}-4 p-77 \]

Ask by Gibbs Rojas. in the United States
Mar 14,2025

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\( p^{2}-4p-77 = (p-11)(p+7) \)

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To factor the quadratic expression \( p^{2}-4 p-77 \), we start by looking for two numbers that multiply to \(-77\) (the constant term) and add up to \(-4\) (the coefficient of the linear term). The two numbers that satisfy these conditions are \(7\) and \(-11\) because \(7 \times (-11) = -77\) and \(7 + (-11) = -4\). Thus, we can factor the expression as: \[ (p + 7)(p - 11) \] In summary, the factored form of the expression is \((p + 7)(p - 11)\).

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