Pregunta
17. Consider the data given below. \( 16,10,8,20,24,12,15,19,25 \) (i) Find the median of the data set. (ii) Find the inter quartile range of the data set.
Ask by Garrett Sanders. in Sri Lanka
Mar 08,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The median is 16 and the interquartile range is 11.
Solución
**Step 1. Sort the Data**
The given data set is:
\[
16,\ 10,\ 8,\ 20,\ 24,\ 12,\ 15,\ 19,\ 25
\]
Sorting the data in ascending order, we have:
\[
8,\ 10,\ 12,\ 15,\ 16,\ 19,\ 20,\ 24,\ 25
\]
**Step 2. Find the Median**
Since there are \(9\) data points (an odd number), the median is the middle value. The middle element is the \(5^\text{th}\) value:
\[
\text{Median} = 16
\]
**Step 3. Find the Interquartile Range (IQR)**
The interquartile range (IQR) is defined as:
\[
\text{IQR} = Q_3 - Q_1
\]
where \(Q_1\) is the first quartile (median of the lower half) and \(Q_3\) is the third quartile (median of the upper half).
*Determine the Lower Half:*
The lower half consists of the values below the median:
\[
8,\ 10,\ 12,\ 15
\]
Since there are \(4\) values, the median of the lower half (i.e., \(Q_1\)) is the average of the middle two values:
\[
Q_1 = \frac{10 + 12}{2} = \frac{22}{2} = 11
\]
*Determine the Upper Half:*
The upper half consists of the values above the median:
\[
19,\ 20,\ 24,\ 25
\]
Similarly, the median of the upper half (i.e., \(Q_3\)) is the average of the middle two values:
\[
Q_3 = \frac{20 + 24}{2} = \frac{44}{2} = 22
\]
*Calculate the IQR:*
\[
\text{IQR} = Q_3 - Q_1 = 22 - 11 = 11
\]
**Final Answers:**
- (i) The median of the data set is \(16\).
- (ii) The interquartile range of the data set is \(11\).
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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Bonus Knowledge
To find the median, first, we need to arrange the data in ascending order: \( 8, 10, 12, 15, 16, 19, 20, 24, 25 \). Since there are 9 numbers (odd), the median is the middle number, which is the 5th number. So, the median is \( 16 \). To find the interquartile range (IQR), we first find the first (Q1) and third quartiles (Q3). For our arranged data, Q1 is the median of the first half (8, 10, 12, 15), which is \( 11 \), and Q3 is the median of the second half (19, 20, 24, 25), which is \( 22 \). The IQR is \( Q3 - Q1 = 22 - 11 = 11 \).

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