Suppose \( f(x)=7 x+9 \) and \( g(x)=\sqrt{x^{2}-3 x+6} \) \( (f \circ g)(x)=\square \) \( (f \circ g)(3)=\square \)

To find the composition of functions \( f \circ g \), we need to substitute the expression for \( g(x) \) into the function \( f(x) \). Given: \( f(x) = 7x + 9 \) \( g(x) = \sqrt{x^2 - 3x + 6} \) Substitute \( g(x) \) into \( f(x) \): \( (f \circ g)(x) = f(g(x)) = 7(g(x)) + 9 \) Substitute the expression for \( g(x) \) into the equation: \( (f \circ g)(x) = 7\sqrt{x^2 - 3x + 6} + 9 \) Now, we need to find \( (f \circ g)(3) \) by substituting \( x = 3 \) into the expression for \( (f \circ g)(x) \): \( (f \circ g)(3) = 7\sqrt{3^2 - 3(3) + 6} + 9 \) Let's calculate \( (f \circ g)(3) \) step by step. The composition of functions \( (f \circ g)(x) = 7\sqrt{x^2 - 3x + 6} + 9 \). To find \( (f \circ g)(3) \), we substitute \( x = 3 \) into the expression: \( (f \circ g)(3) = 7\sqrt{3^2 - 3(3) + 6} + 9 \) Calculating \( (f \circ g)(3) \): \( (f \circ g)(3) = 7\sqrt{6} + 9 \) Therefore, \( (f \circ g)(3) \approx 26.146428 \).