3 Determine the following from the algebraic terms: \( 30 x^{3} y^{2} z ; \) \( \begin{array}{ll}\text { 3.3.1 } & \text { The prime factors of each term. } \\ 3.3 .2 & \text { The lowest common multiple (LCM) } \\ 3.3 .3 & \text { The highest common factor (HCF) }\end{array} \)
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The expression \( 30 x^{3} y^{2} z \) can be broken down into its prime factors. For \( 30 \), the prime factors are \( 2 \), \( 3 \), and \( 5 \). In terms of the variables, \( x^{3} \) consists of three \( x \)'s, \( y^{2} \) has two \( y \)'s, and \( z \) represents one \( z \). So, the full breakdown of prime factors is \( 2, 3, 5, x, x, x, y, y, z \). When finding the lowest common multiple (LCM) of \( 30, x^{3}, y^{2}, z \), we take the highest power of each factor. The LCM will be \( 2^{1} \cdot 3^{1} \cdot 5^{1} \cdot x^{3} \cdot y^{2} \cdot z^{1} = 30 x^{3} y^{2} z \). For the highest common factor (HCF), we look for the minimum power of each factor present, which is simply \( 1 \) for the constants, \( x^{0} \) for \( x \) (not present in all), \( y^{0} \) for \( y \) (not present in all), and \( z^{0} \) for \( z \) (not present in all), resulting in an HCF of \( 1 \).
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