\[ \begin{array}{l}\text { Find the value. } \\ \ln \left(\frac{1}{e^{6}}\right) \\ \ln \left(\frac{1}{e^{6}}\right)=\square\end{array} \]

To simplify \(\ln \left(\frac{1}{e^{6}}\right)\), we can use the property of logarithms that states \(\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\). In this case, we have: \[ \ln\left(\frac{1}{e^{6}}\right) = \ln(1) - \ln(e^{6}). \] Since \(\ln(1) = 0\) and \(\ln(e^{6}) = 6\), we can substitute these values in: \[ \ln\left(\frac{1}{e^{6}}\right) = 0 - 6 = -6. \] Thus, the final value is: \[ \ln \left(\frac{1}{e^{6}}\right) = -6. \]