Find the HCF of the following numbers: $$ 20 ; 32 $$; and 48

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UpStudy AI · Accepted Answer

1. Write the prime factorization of each number:  
   - $$20 = 2^2 \times 5$$  
   - $$32 = 2^5$$  
   - $$48 = 2^4 \times 3$$

2. Identify the common prime factors across all numbers.  
   The only common prime factor is $$2$$.

3. Choose the smallest exponent of $$2$$ found in the factorizations.  
   The exponents are:  
   - $$2^2$$ in $$20$$  
   - $$2^5$$ in $$32$$  
   - $$2^4$$ in $$48$$  
   The smallest exponent is $$2$$, so the factor is $$2^2$$.

4. Therefore, the Highest Common Factor (HCF) is:  
   $$
   2^2 = 4
   $$
The HCF of 20, 32, and 48 is 4.

Find the HCF of the following numbers: \( 20 ; 32 \); and 48

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