\( 5 \frac{1}{2}-n+3 \) for \( n=3 \frac{1}{3} \)
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To solve the expression \( 5 \frac{1}{2}-n+3 \) when \( n=3 \frac{1}{3} \), first convert the mixed numbers to improper fractions. \( 5 \frac{1}{2} = \frac{11}{2} \) and \( 3 \frac{1}{3} = \frac{10}{3} \). Now substitute \( n \) into the expression: \[ \frac{11}{2} - \frac{10}{3} + 3 \] Next, convert 3 to a fraction with a common denominator: \[ 3 = \frac{9}{3} \] Now combine the fractions: \[ \frac{11}{2} - \frac{10}{3} + \frac{9}{3} \] First, combine \(-\frac{10}{3} + \frac{9}{3} = -\frac{1}{3}\): \[ \frac{11}{2} - \frac{1}{3} \] To subtract these, convert \(\frac{11}{2}\) to a common denominator of 6: \[ \frac{11}{2} = \frac{33}{6} \] And convert \(-\frac{1}{3}\) to a fraction with a common denominator of 6: \[ -\frac{1}{3} = -\frac{2}{6} \] Now, perform the subtraction: \[ \frac{33}{6} - \frac{2}{6} = \frac{31}{6} \] Thus, the final answer is: \[ 5 \frac{1}{2} - 3 \frac{1}{3} + 3 = \frac{31}{6} \] or \( 5 \frac{1}{6} \) when converted back to a mixed number.
