Find the solution of the system of equations. \[ \begin{array}{r}-10 x+8 y=-44 \\ 4 x+8 y=40\end{array} \]

Solve the system of equations \( -10x+8y=-44;4x+8y=40 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}-10x+8y=-44\\4x+8y=40\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x=\frac{22+4y}{5}\\4x+8y=40\end{array}\right.\) - step2: Substitute the value of \(x:\) \(4\times \frac{22+4y}{5}+8y=40\) - step3: Simplify: \(\frac{4\left(22+4y\right)}{5}+8y=40\) - step4: Multiply both sides of the equation by LCD: \(\left(\frac{4\left(22+4y\right)}{5}+8y\right)\times 5=40\times 5\) - step5: Simplify the equation: \(88+56y=200\) - step6: Move the constant to the right side: \(56y=200-88\) - step7: Subtract the numbers: \(56y=112\) - step8: Divide both sides: \(\frac{56y}{56}=\frac{112}{56}\) - step9: Divide the numbers: \(y=2\) - step10: Substitute the value of \(y:\) \(x=\frac{22+4\times 2}{5}\) - step11: Calculate: \(x=6\) - step12: Calculate: \(\left\{ \begin{array}{l}x=6\\y=2\end{array}\right.\) - step13: Check the solution: \(\left\{ \begin{array}{l}x=6\\y=2\end{array}\right.\) - step14: Rewrite: \(\left(x,y\right) = \left(6,2\right)\) The solution to the system of equations is \( (x, y) = (6, 2) \).