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7. Cannot determine the simple interest without the rate of interest (\( r \)) and the time (\( t \)).
8. It will take 7 years for R6,000 to grow to R8,520 at a 6% simple interest rate.
9. Temoso owes the bank R1,259.71 at the end of three years.
10. Tom's annual rent is R15,000. After an 8.5% increase, his monthly rent will be R1,356.25.
Solución
Alright, I need to solve these four financial problems step by step. Let's tackle them one by one.
**Problem 7: Calculate the simple interest on R1 200.**
The formula for simple interest is:
\[ S I = \frac{P \times r \times t}{100} \]
Where:
- \( P \) is the principal amount,
- \( r \) is the rate of interest per annum,
- \( t \) is the time in years.
Given:
- \( P = R1,200 \)
- \( r = ? \) (not provided)
- \( t = ? \) (not provided)
Wait, the problem doesn't provide the rate of interest (\( r \)) or the time (\( t \)). Without these values, I can't calculate the simple interest. Maybe I missed something. Let me read the question again.
Oh, I see. The problem only provides the principal amount but not the rate or time. Since both \( r \) and \( t \) are missing, it's impossible to compute the simple interest. Perhaps there's an assumption that \( r \) and \( t \) are standard values, but without explicit numbers, I can't proceed. Maybe I should consider common rates and times, but that would be speculative.
Alternatively, maybe the problem expects me to express the simple interest in terms of \( r \) and \( t \). Let's try that.
\[ S I = \frac{1,200 \times r \times t}{100} \]
\[ S I = 12 \times r \times t \]
So, the simple interest is 12 times the rate multiplied by the time. But this doesn't give a numerical value. I think the problem might be incomplete or missing some information.
**Problem 8: How long will it take for R6 000 invested at 6% per annum simple interest to grow to R8,520?**
Using the simple interest formula:
\[ S I = \frac{P \times r \times t}{100} \]
Where:
- \( P = R6,000 \)
- \( r = 6\% \)
- \( S I = R8,520 - R6,000 = R2,520 \) (since the total amount after interest is R8,520)
Plugging in the values:
\[ 2,520 = \frac{6,000 \times 6 \times t}{100} \]
\[ 2,520 = \frac{36,000 \times t}{100} \]
\[ 2,520 = 360 \times t \]
\[ t = \frac{2,520}{360} \]
\[ t = 7 \text{ years} \]
So, it will take 7 years for the investment to grow from R6,000 to R8,520 at a 6% simple interest rate.
**Problem 9: Temoso borrowed R1,000 from the bank for 3 years at 8% compound interest. Without using a formula, calculate how much Temoso owes the bank at the end of three years.**
Compound interest means the interest is calculated on both the principal and the accumulated interest from previous periods. Without a formula, I'll have to calculate it step by step.
First year:
- Principal: R1,000
- Interest: \( 1,000 \times 8\% = R80 \)
- Total after first year: \( 1,000 + 80 = R1,080 \)
Second year:
- Principal: R1,080
- Interest: \( 1,080 \times 8\% = R86.40 \)
- Total after second year: \( 1,080 + 86.40 = R1,166.40 \)
Third year:
- Principal: R1,166.40
- Interest: \( 1,166.40 \times 8\% = R93.312 \)
- Total after third year: \( 1,166.40 + 93.312 = R1,259.712 \)
Rounding to two decimal places, Temoso owes the bank R1,259.71 at the end of three years.
**Problem 10: Tom pays R1,250 rent every month. What is his annual rent? If his rent is increased by 8.5% at the end of the year, what will his increased monthly rent be?**
First, calculate the annual rent:
- Monthly rent: R1,250
- Number of months in a year: 12
- Annual rent: \( 1,250 \times 12 = R15,000 \)
Next, calculate the increased monthly rent after an 8.5% increase:
- Current monthly rent: R1,250
- Increase: \( 1,250 \times 8.5\% = R106.25 \)
- New monthly rent: \( 1,250 + 106.25 = R1,356.25 \)
So, Tom's annual rent is R15,000, and his increased monthly rent after an 8.5% hike is R1,356.25.
Respondido por UpStudy AI y revisado por un tutor profesional
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