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7. Calculate the simple interest on R1 200 ot \( S I=\frac{P r I}{100} \) \( (P= \) principal amount, \( t= \) time (number of \( y \) simple interest). 8. How long will it take for R6 000 invested at \( 6 \% \) per annum simple in grow to \( R 8520 \) ? (Use the formula \( S I=\frac{P r i}{100} \) ) 9. Temoso borrowed R1 000 from the bank for 3 years at \( 8 \% \) compound Without using a formula, calculate how much Temoso owes the ban end of three years. 10. Tom pays \( R 1250 \) rent every month. What is his annual rent? If his rent is by \( 8,5 \% \) at the end of the year, what will his increased monthly rent be?

Ask by Campbell Bernard. in South Africa
Feb 12,2025

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7. Cannot determine the simple interest without the rate of interest (\( r \)) and the time (\( t \)). 8. It will take 7 years for R6,000 to grow to R8,520 at a 6% simple interest rate. 9. Temoso owes the bank R1,259.71 at the end of three years. 10. Tom's annual rent is R15,000. After an 8.5% increase, his monthly rent will be R1,356.25.

Solución

Alright, I need to solve these four financial problems step by step. Let's tackle them one by one. **Problem 7: Calculate the simple interest on R1 200.** The formula for simple interest is: \[ S I = \frac{P \times r \times t}{100} \] Where: - \( P \) is the principal amount, - \( r \) is the rate of interest per annum, - \( t \) is the time in years. Given: - \( P = R1,200 \) - \( r = ? \) (not provided) - \( t = ? \) (not provided) Wait, the problem doesn't provide the rate of interest (\( r \)) or the time (\( t \)). Without these values, I can't calculate the simple interest. Maybe I missed something. Let me read the question again. Oh, I see. The problem only provides the principal amount but not the rate or time. Since both \( r \) and \( t \) are missing, it's impossible to compute the simple interest. Perhaps there's an assumption that \( r \) and \( t \) are standard values, but without explicit numbers, I can't proceed. Maybe I should consider common rates and times, but that would be speculative. Alternatively, maybe the problem expects me to express the simple interest in terms of \( r \) and \( t \). Let's try that. \[ S I = \frac{1,200 \times r \times t}{100} \] \[ S I = 12 \times r \times t \] So, the simple interest is 12 times the rate multiplied by the time. But this doesn't give a numerical value. I think the problem might be incomplete or missing some information. **Problem 8: How long will it take for R6 000 invested at 6% per annum simple interest to grow to R8,520?** Using the simple interest formula: \[ S I = \frac{P \times r \times t}{100} \] Where: - \( P = R6,000 \) - \( r = 6\% \) - \( S I = R8,520 - R6,000 = R2,520 \) (since the total amount after interest is R8,520) Plugging in the values: \[ 2,520 = \frac{6,000 \times 6 \times t}{100} \] \[ 2,520 = \frac{36,000 \times t}{100} \] \[ 2,520 = 360 \times t \] \[ t = \frac{2,520}{360} \] \[ t = 7 \text{ years} \] So, it will take 7 years for the investment to grow from R6,000 to R8,520 at a 6% simple interest rate. **Problem 9: Temoso borrowed R1,000 from the bank for 3 years at 8% compound interest. Without using a formula, calculate how much Temoso owes the bank at the end of three years.** Compound interest means the interest is calculated on both the principal and the accumulated interest from previous periods. Without a formula, I'll have to calculate it step by step. First year: - Principal: R1,000 - Interest: \( 1,000 \times 8\% = R80 \) - Total after first year: \( 1,000 + 80 = R1,080 \) Second year: - Principal: R1,080 - Interest: \( 1,080 \times 8\% = R86.40 \) - Total after second year: \( 1,080 + 86.40 = R1,166.40 \) Third year: - Principal: R1,166.40 - Interest: \( 1,166.40 \times 8\% = R93.312 \) - Total after third year: \( 1,166.40 + 93.312 = R1,259.712 \) Rounding to two decimal places, Temoso owes the bank R1,259.71 at the end of three years. **Problem 10: Tom pays R1,250 rent every month. What is his annual rent? If his rent is increased by 8.5% at the end of the year, what will his increased monthly rent be?** First, calculate the annual rent: - Monthly rent: R1,250 - Number of months in a year: 12 - Annual rent: \( 1,250 \times 12 = R15,000 \) Next, calculate the increased monthly rent after an 8.5% increase: - Current monthly rent: R1,250 - Increase: \( 1,250 \times 8.5\% = R106.25 \) - New monthly rent: \( 1,250 + 106.25 = R1,356.25 \) So, Tom's annual rent is R15,000, and his increased monthly rent after an 8.5% hike is R1,356.25.

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Bonus Knowledge

To calculate the simple interest on R1,200 for a period "t" years at a certain interest rate, you'll use the given formula: \( S I = \frac{P r t}{100} \). If, for example, the interest rate is 5%, you plug in the numbers to get \( S I = \frac{1200 \times 5 \times t}{100} \). Just remember, the higher the time period or interest rate, the more money you earn! In another scenario, to determine how long it will take for R6,000 to grow to R8,520 at 6% simple interest per annum, you will first find the interest earned which is R2,520 (R8,520 - R6,000). Then, with the formula rearranged, you can find 't' by rearranging \( S I = P r t / 100 \) to solve for 't'. Don’t forget to ensure cents are accounted for so you don't lose any of your hard-earned cash!

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