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Summanize the pertinent information obtained by applying the graphing strategy and sketch the graph of \( y=f(x) \). \( f(x)= \) In \( (x+3)-2 \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function \( f \) is decteasing on the subintorval(s) (Iype your answer in interval notation. Use a comma to separate answers as needed.) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function \( f \) has a local maximum at \( x= \) (Type an exact answer. Use a comma to separate answers as nceded.) B. The function f has no local maximuril. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The function f has a local minimum at \( \mathrm{x}= \) (Type an exact answer. Use a comma to separate answers as needed.) B. The function f has no local minimum.

Ask by Gordon Rodriguez. in the United States
Mar 11,2025

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The function \( f(x) = \ln(x + 3) - 2 \) is always increasing on the interval \( (-3, \infty) \). It has no local maxima or minima.

Solución

To analyze the function \( f(x) = \ln(x + 3) - 2 \), we will follow these steps: 1. **Determine the domain of the function.** 2. **Find the derivative to analyze increasing/decreasing behavior.** 3. **Identify critical points for local maxima and minima.** 4. **Sketch the graph based on the findings.** ### Step 1: Determine the Domain The function \( f(x) = \ln(x + 3) - 2 \) is defined when the argument of the logarithm is positive: \[ x + 3 > 0 \implies x > -3 \] Thus, the domain of \( f \) is \( (-3, \infty) \). ### Step 2: Find the Derivative To find the intervals where the function is increasing or decreasing, we need to compute the derivative \( f'(x) \): \[ f'(x) = \frac{d}{dx}(\ln(x + 3)) = \frac{1}{x + 3} \] The derivative \( f'(x) \) is positive when \( x + 3 > 0 \) (which is always true in the domain) and negative when \( x + 3 < 0 \) (not applicable here). Therefore, \( f'(x) > 0 \) for all \( x > -3 \). ### Step 3: Identify Critical Points Since \( f'(x) > 0 \) for all \( x > -3 \), there are no critical points where the derivative is zero. Thus, there are no local maxima or minima. ### Step 4: Summary of Findings - **Decreasing Intervals:** The function \( f \) is not decreasing on any interval. - **Local Maximum:** The function \( f \) has no local maximum. - **Local Minimum:** The function \( f \) has no local minimum. ### Final Answers 1. The function \( f \) is decreasing on the interval(s): **None** (or you can write it as an empty set). 2. The function \( f \) has a local maximum at \( x = \): **None**. 3. The function \( f \) has a local minimum at \( x = \): **None**. ### Sketch of the Graph The graph of \( f(x) = \ln(x + 3) - 2 \) will show a logarithmic curve starting from the point \( (-3, -2) \) and increasing without bound as \( x \) increases. The graph approaches the vertical asymptote at \( x = -3 \) and continues to rise as \( x \) moves to the right. If you need a visual representation, I can plot the graph for you. Would you like me to do that?

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Beyond the Answer

To analyze the function \( f(x) = \ln(x + 3) - 2 \), we start by identifying its domain. The natural logarithm function is defined for \( x + 3 > 0 \), meaning \( x > -3 \). As \( x \) approaches -3 from the right, \( f(x) \) approaches negative infinity, creating a vertical asymptote. The function \( f(x) \) is increasing for all \( x > -3 \) since the derivative \( f'(x) = \frac{1}{x + 3} > 0 \) in that interval. Thus, there are no intervals where the function decreases. Since the function is always increasing, there are no local maxima or minima, making both options for local max and min as "no local maximum" and "no local minimum." In summary: - The function is increasing on the interval \( (-3, \infty) \). - The function has no local maximum. - The function has no local minimum.

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