1) An isosceles triangle has an angle that measures $$ 100^{\circ} $$. What measures are possible for the other two angles? Choose all that apply.

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In an isosceles triangle, two angles are equal, and the sum of all angles in a triangle is always $$ 180^{\circ} $$.

Given that one angle measures $$ 100^{\circ} $$, we can denote the other two equal angles as $$ x $$. The equation for the sum of the angles in the triangle can be set up as follows:

$$
100^{\circ} + x + x = 180^{\circ}
$$

This simplifies to:

$$
100^{\circ} + 2x = 180^{\circ}
$$

Now, we can solve for $$ x $$:

$$
2x = 180^{\circ} - 100^{\circ}
$$
$$
2x = 80^{\circ}
$$
$$
x = \frac{80^{\circ}}{2} = 40^{\circ}
$$

Thus, the measures of the other two angles in the isosceles triangle are both $$ 40^{\circ} $$.

In conclusion, the possible measures for the other two angles are $$ 40^{\circ} $$ each.
The other two angles are both $$ 40^{\circ} $$.

1) An isosceles triangle has an angle that measures \( 100^{\circ} \). What measures are possible for the other two angles? Choose all that apply.

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