Pregunta
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(3) Which expression is equivalent to \( 3(2 x+4 y)-y \) ? A \( 17 x y \) B \( 6 x+12 \) C \( 3(6 x y)-y \) D \( 6(x+2 y)-y \) Kimani chose C as the correct answer. How might she have gotten that answer?

Ask by Gross Fowler. in the United States
Mar 08,2025

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Kimani likely combined the terms \(2x\) and \(4y\) incorrectly by adding their coefficients, thinking \(2x + 4y = 6xy\), and then multiplied by 3 to get \(3(6xy) - y\), which matches option C.

Solución

1. Kimani started with the expression \[ 3(2x+4y)-y. \] 2. She mistakenly “combined” the terms \(2x\) and \(4y\) as if they were like terms. In her reasoning, she treated the sum as: \[ 2x+4y \stackrel{\text{incorrectly}}{=} (2+4)xy = 6xy. \] 3. Then, substituting her incorrect combination into the original expression, she obtained: \[ 3(2x+4y)-y = 3(6xy)-y. \] 4. This is exactly answer C, although the error lies in assuming that \(2x\) and \(4y\) could be added by combining their numerical coefficients and then multiplying by \(xy\). In reality, because \(x\) and \(y\) are different variables, the terms \(2x\) and \(4y\) are not like terms and cannot be combined in that way. The proper approach would have been to distribute: \[ 3(2x+4y)-y = 6x + 12y - y = 6x + 11y. \]

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Bonus Knowledge

Kimani might have chosen C because it appears to simplify in a way that relates to the original expression. She may have noticed \(3(6xy) - y\) as aligning with the multiplication of \(3\) through \(2x + 4y\), mistakenly thinking they were equivalent through distributive properties without fully expanding both expressions. However, if she had fully expanded \(3(2x + 4y) - y\) to \(6x + 12y - y\), resulting in \(6x + 11y\), she would have realized that none of the answer choices (including C) matched this final form. Understanding how to properly distribute and combine like terms could have saved her from this mix-up!

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