What are the \( x \)-intercepts of the following function? \( f(x)=(x-2)(x+5)(x-7) \) \( 2,5,7 \) \( -2,5,-7 \) \( 2,-5,7 \) 5,7
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To find the \( x \)-intercepts of the function \( f(x)=(x-2)(x+5)(x-7) \), you simply set the function equal to zero: \( f(x) = 0 \). This leads to three equations: \( x - 2 = 0 \), \( x + 5 = 0 \), and \( x - 7 = 0 \). Solving these gives the intercepts \( x = 2 \), \( x = -5 \), and \( x = 7 \). So, the \( x \)-intercepts are \( 2, -5, 7 \). A handy way to remember finding \( x \)-intercepts is to keep in mind this simple method: **set the factored equation to zero!** Each factor gives you a direct path to the intercepts. Just be cautious about negative signs!