State how the divisibility tests for 3 and 9 are similar. wses Determine whether or not the results of the fo \( \begin{array}{ll}\text { a. } 54 \div 2 & \text { b. } 150 \div 9\end{array} \)

Both the divisibility tests for 3 and 9 rely on the sum of the digits in a number. If the sum of the digits is divisible by 3, then the original number is also divisible by 3. For 9, the rule is similar; if the sum of the digits is divisible by 9, then the original number is divisible by 9. This means that any number divisible by 9 will also be divisible by 3! Now, let’s look at the examples! For \(54\) divided by \(2\): The result is \(27\), and since \(54\) is an even number, it is divisible by \(2\). For \(150\) divided by \(9\): Here, the sum of the digits \(1 + 5 + 0 = 6\) is not divisible by \(9\), so \(150\) is not divisible by \(9\) either, and the division results in \(16.67\) (or \(16\) remainder \(6\)).