Perform the indicated operations. Write the answer in standard form, \( a+b i \). \[ (\sqrt{10}+\sqrt{6} i)(\sqrt{10}-\sqrt{6} i)=\square \]
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To perform the operations on the given complex numbers, we can use the formula for multiplying two binomials, which resembles the difference of squares. \[ (\sqrt{10}+\sqrt{6} i)(\sqrt{10}-\sqrt{6} i) = (\sqrt{10})^2 - (\sqrt{6} i)^2 \] Calculating each part gives us: \[ (\sqrt{10})^2 = 10 \] \[ (\sqrt{6} i)^2 = (\sqrt{6})^2 \cdot (i)^2 = 6 \cdot (-1) = -6 \] Now we substitute these values back into our equation: \[ 10 - (-6) = 10 + 6 = 16 \] Thus, the result in standard form \( a + bi \) is: \[ \boxed{16 + 0i} \]
