Suppose that the function \( h \) is defined, for all real numbers, as follows. \[ h(x)=\left\{\begin{array}{ll}-2 & \text { if } x \neq 2 \\ 3 & \text { if } x=2\end{array}\right. \] Find \( h(0), h(2) \), and \( h(4) \) \( h(0)=\square \)

To find the values of the function \( h(x) \): 1. For \( h(0) \): Since \( 0 \neq 2 \), we use the first case of the function's definition. Thus, \( h(0) = -2 \). 2. For \( h(2) \): Here, we have \( x = 2 \), so we use the second case of the function's definition. Therefore, \( h(2) = 3 \). 3. For \( h(4) \): Since \( 4 \neq 2 \), we again use the first case. Thus, \( h(4) = -2 \). In summary: - \( h(0) = -2 \) - \( h(2) = 3 \) - \( h(4) = -2 \) Hence, \( h(0) = -2 \).