Let \( A=\left[\begin{array}{ll}1 & 7 \\ 6 & 9\end{array}\right] \) Find \( -5 A \) \( -5 A=\square \)

To find \( -5 A \), you simply multiply each entry in the matrix \( A \) by \(-5\). So, we start with the matrix \[ A = \left[\begin{array}{ll}1 & 7 \\ 6 & 9\end{array}\right] \] Now, calculating \( -5 A \): \[ -5 A = -5 \cdot \left[\begin{array}{ll}1 & 7 \\ 6 & 9\end{array}\right] = \left[\begin{array}{ll}-5 \cdot 1 & -5 \cdot 7 \\ -5 \cdot 6 & -5 \cdot 9\end{array}\right] \] This results in: \[ -5 A = \left[\begin{array}{ll}-5 & -35 \\ -30 & -45\end{array}\right] \] Thus, \[ -5 A = \left[\begin{array}{ll}-5 & -35 \\ -30 & -45\end{array}\right] \]