\begin{tabular}{l} Solve using substitution. \\ \( \qquad \begin{array}{l}y=-5 x+8 \\ y=-2 x+5\end{array} \) \\ \hline\end{tabular}
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To solve the system of equations using substitution, start with the first equation \( y = -5x + 8 \) and substitute this expression for \( y \) in the second equation \( y = -2x + 5 \). This gives us: \[ -5x + 8 = -2x + 5 \] Now, solve for \( x \): 1. Add \( 5x \) to both sides: \[ 8 = 3x + 5 \] 2. Subtract \( 5 \) from both sides: \[ 3 = 3x \] 3. Divide by \( 3 \): \[ x = 1 \] Next, substitute \( x = 1 \) back into the first equation to find \( y \): \[ y = -5(1) + 8 = -5 + 8 = 3 \] Thus, the solution to the system of equations is \( (1, 3) \). Now you can check your solution by substituting both \( x \) and \( y \) into the second equation \( y = -2x + 5 \): \[ 3 = -2(1) + 5 \quad \text{gives} \quad 3 = -2 + 5 \quad \text{which is true}. \] So the values \( (1, 3) \) satisfy both equations!
