\begin{tabular}{l|l|l} 5. What is the product of \( 2 x+3 \) & \( \begin{array}{l}\text { 6. What is the slope for the } \\ \text { equation }-3 y-2 x=-12 ?\end{array} \) \\ and \( -5 x+6 ? \)\end{tabular}

To find the product of \( 2x + 3 \) and \( -5x + 6 \), you need to use the distributive property. Multiply each term in the first polynomial by each term in the second polynomial: \[ (2x + 3)(-5x + 6) = 2x \cdot -5x + 2x \cdot 6 + 3 \cdot -5x + 3 \cdot 6 = -10x^2 + 12x - 15x + 18 \] Now combine the like terms: \[ -10x^2 - 3x + 18 \] So the product is \( -10x^2 - 3x + 18 \). To find the slope of the equation \(-3y - 2x = -12\), first, you want to put it in slope-intercept form (\(y = mx + b\)). Start by isolating \(y\): \[ -3y = 2x - 12 \Rightarrow y = -\frac{2}{3}x + 4 \] From this equation, you can see that the slope \(m\) is \(-\frac{2}{3}\). So, the slope for the given equation is \(-\frac{2}{3}\).