Solve the system by elimination. Enter your answer as an ordered pair or type none or infinite. \( \left\{\begin{array}{c}8 x-3 y=-11 \\ 2 x-5 y=27\end{array}\right. \)

Solve the system of equations \( 8x-3y=-11;2x-5y=27 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}8x-3y=-11\\2x-5y=27\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x=\frac{-11+3y}{8}\\2x-5y=27\end{array}\right.\) - step2: Substitute the value of \(x:\) \(2\times \frac{-11+3y}{8}-5y=27\) - step3: Reduce the fraction: \(\frac{-11+3y}{4}-5y=27\) - step4: Multiply both sides of the equation by LCD: \(\left(\frac{-11+3y}{4}-5y\right)\times 4=27\times 4\) - step5: Simplify the equation: \(-11-17y=108\) - step6: Move the constant to the right side: \(-17y=108+11\) - step7: Add the numbers: \(-17y=119\) - step8: Change the signs: \(17y=-119\) - step9: Divide both sides: \(\frac{17y}{17}=\frac{-119}{17}\) - step10: Divide the numbers: \(y=-7\) - step11: Substitute the value of \(y:\) \(x=\frac{-11+3\left(-7\right)}{8}\) - step12: Simplify: \(x=-4\) - step13: Calculate: \(\left\{ \begin{array}{l}x=-4\\y=-7\end{array}\right.\) - step14: Check the solution: \(\left\{ \begin{array}{l}x=-4\\y=-7\end{array}\right.\) - step15: Rewrite: \(\left(x,y\right) = \left(-4,-7\right)\) The solution to the system of equations by the elimination method is \( (x, y) = (-4, -7) \).