b) $$ -3^{2}+(-2)^{3}+\sqrt[3]{64} $$

Question

UpStudy AI · Accepted Answer

1. Evaluate $$ -3^{2} $$:  
   Since exponentiation takes precedence over the negation,  
   $$
   -3^{2} = -(3^2) = -9.
   $$

2. Evaluate $$ (-2)^{3} $$:  
   $$
   (-2)^3 = (-2) \times (-2) \times (-2) = -8.
   $$

3. Evaluate $$ \sqrt[3]{64} $$:  
   Since $$ 4^3 = 64 $$,  
   $$
   \sqrt[3]{64} = 4.
   $$

4. Combine the results:  
   $$
   -9 + (-8) + 4 = -9 - 8 + 4 = -13.
   $$

Therefore, the final answer is $$ -13 $$.
The final answer is $$ -13 $$.

b) \( -3^{2}+(-2)^{3}+\sqrt[3]{64} \)