A coin is tossed and a six-sided die numbered 1 through 6 is rolled. Find the probability of tossing a tail and then rolling a number greater than 4 . The probability of tossing a tail and then rolling a number greater than 4 is (Round to three decimal places as needed.)

To solve this probability problem, let's break it down into two parts. The probability of tossing a tail (T) with a coin is 1/2, as there are two possible outcomes: heads (H) or tails (T). For the six-sided die, the outcomes greater than 4 are 5 and 6. There are two favorable outcomes out of six total outcomes, giving a probability of 2/6 or 1/3 for rolling a number greater than 4. Now, to find the joint probability of both events happening, we multiply the probabilities of the individual events: P(T and >4) = P(T) * P(>4) = (1/2) * (1/3) = 1/6. To round this to three decimal places, we calculate: 1/6 ≈ 0.167. So, the final probability of tossing a tail and then rolling a number greater than 4 is approximately **0.167**.