QUESTION 4 HEAT 4.1 I 90 litre cylinder is filled with nitrogen to capacity at a pressure of \( 20,11 \mathrm{kPa} \). If the cylinder enlarges, the pressure drops to 11 kPa . Calculate the increase in the volume of the cylinder.
Solución de inteligencia artificial de Upstudy
Responder
Solución

¡Inicia sesión para desbloquear respuestas gratis!
Una plataforma de aprendizaje en la que confían millones de estudiantes y profesores reales.

Respondido por UpStudy AI y revisado por un tutor profesional
Mind Expander
To solve this, we can use Boyle's Law, which states that for a given mass of gas at constant temperature, the product of the pressure and volume is constant (P1V1 = P2V2). Given: - Initial pressure \( P_1 = 20.11 \, \text{kPa} \) - Initial volume \( V_1 = 90 \, \text{litres} \) - Final pressure \( P_2 = 11 \, \text{kPa} \) We need to find the final volume \( V_2 \). Using Boyle's Law: \[ P_1V_1 = P_2V_2 \] Substituting the known values: \[ 20.11 \, \text{kPa} \times 90 \, \text{litres} = 11 \, \text{kPa} \times V_2 \] Calculating \( 20.11 \times 90 = 1809.9 \, \text{kPa.litres} \): \[ 1809.9 \, \text{kPa.litres} = 11 \, \text{kPa} \times V_2 \] Now, solve for \( V_2 \): \[ V_2 = \frac{1809.9}{11} \approx 164.54 \, \text{litres} \] The increase in volume is: \[ V_2 - V_1 = 164.54 - 90 = 74.54 \, \text{litres} \] So, the increase in the volume of the cylinder is approximately \( 74.54 \, \text{litres} \).
