QUESTION 1 [11] 1.1 Given: \( \sqrt{9+25} ; \pi-4 ; \sqrt{-27} ; \frac{2}{3} ; \frac{19}{7}: \sqrt{-27} \) From the list given above, write down: \( \begin{array}{ll}1.1 .1 & \text { A natural number. } \\ \begin{array}{ll}1.12 & \text { A negative irrational number. } \\ 1.13 & \text { A non-real number. }\end{array}\end{array} \).

To answer your question based on the expressions provided: 1.1.1: The natural number from the list is \( \sqrt{9 + 25} = \sqrt{34} \). Since \( \sqrt{34} \) is approximately 5.83, it does not fit the natural number criteria. However, none of the other expressions yield a natural number either. Thus, there is no natural number present in the list provided. 1.1.2: The negative irrational number from the list is \( \pi - 4 \). Since \( \pi \) is approximately 3.14, subtracting 4 gives a negative value (~-0.86), which is also irrational since it cannot be simplified into a fraction of two integers. 1.1.3: The non-real number from the list is \( \sqrt{-27} \). This expression represents an imaginary number since the square root of a negative number involves the imaginary unit \( i \). Specifically, \( \sqrt{-27} = i\sqrt{27} = 3i\sqrt{3} \).