If \( f(x)=x^{m+4} \), find \( f^{\prime}(x) \) at point \( (1,2) \)
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Bonus Knowledge
To find the derivative \( f'(x) \) of the function \( f(x) = x^{m+4} \), we use the power rule of differentiation. The power rule states that the derivative of \( x^n \) is \( n \cdot x^{n-1} \). Applying this to our function, we have: \[ f'(x) = (m+4) \cdot x^{(m+4)-1} = (m+4) \cdot x^{m+3} \] Now, we need to evaluate \( f'(x) \) at the point \( x = 1 \): \[ f'(1) = (m+4) \cdot 1^{m+3} = m + 4 \] Given that the output at this point is 2 (from point \( (1,2) \)), we can set up the equation: \[ m + 4 = 2 \] Solving for \( m \) gives: \[ m = 2 - 4 = -2 \] Thus, \( f'(1) = 2 \) when \( m = -2 \). Therefore, \( f^{\prime}(1) = 2 \) at the point \( (1, 2) \) when \( f(x) = x^{m+4} \).
