(c) Calculate the value of \( \frac{p}{7} \times \frac{2}{3}=\frac{10}{21} \) \( \begin{array}{ll}\text { (1) } & \text { (2) } \frac{2}{3} \times \frac{p}{4}=\frac{1}{2} \\ \text { (3) } \frac{-2}{3} \times \frac{4}{p}=\frac{8}{15} & \text { (4) } 1 \frac{1}{2} \times \frac{p}{4}=\frac{15}{8}\end{array} \)

To calculate the value of \( p \) in each equation, start by rewriting each equation to isolate \( p \). For the first equation, \( \frac{p}{7} \times \frac{2}{3} = \frac{10}{21} \), we multiply both sides by the reciprocal of \( \frac{2}{3} \): \[ \frac{p}{7} = \frac{10}{21} \times \frac{3}{2} = \frac{15}{21} = \frac{5}{7} \] Multiplying both sides by 7 gives \( p = 5 \). Now, let's tackle the other equations using a similar approach! Engage your mathematical superhero skills and you'll discover \( p \) for each condition. Remember to double-check your work for those sneaky calculation errors! In addition to these fun calculations, it's useful to remember that fractions are like a dance: they can be tricky at times but with practice, you’ll find the rhythm! Divide, multiply, and don't forget to simplify whenever you can; it's your best friend in fraction world!