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To simplify the expression \( (x-3)^{2} - (x+4)^{2} \), we can use the difference of squares formula, which states that \( a^2 - b^2 = (a-b)(a+b) \). Here, let's denote: - \( a = x - 3 \) - \( b = x + 4 \) Now, we have: \[ (x-3)^{2} - (x+4)^{2} = ( (x-3) - (x+4) )((x-3) + (x+4)) \] Calculating \( (x-3) - (x+4) \): \[ (x - 3) - (x + 4) = x - 3 - x - 4 = -7 \] Calculating \( (x-3) + (x+4) \): \[ (x - 3) + (x + 4) = x - 3 + x + 4 = 2x + 1 \] Putting it all together, we substitute back: \[ (x-3)^{2} - (x+4)^{2} = (-7)(2x + 1) \] Now, simply multiply this out: \[ = -14x - 7 \] Thus, the simplified expression is: \[ \boxed{-14x - 7} \]
