Pregunta
\( 1 \leftarrow \quad \begin{array}{l}\text { Evaluate the polynomial when } \mathrm{x}=1 \text { and } \mathrm{y}=-8 \\ \mathrm{x}^{2}-\mathrm{y}^{2}+\mathrm{xy}\end{array} \)
Ask by Cross Harper. in the United States
Feb 17,2025
Solución de inteligencia artificial de Upstudy
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When x = 1 and y = -8, the polynomial x² - y² + xy equals -71.
Solución
We substitute x = 1 and y = -8 into the polynomial x² - y² + xy.
Step 1: Compute each term:
• x² = 1² = 1
• y² = (-8)² = 64
• xy = 1 × (-8) = -8
Step 2: Substitute these into the expression:
x² - y² + xy = 1 - 64 - 8
Step 3: Simplify:
1 - 64 = -63
-63 - 8 = -71
Thus, the evaluated polynomial is -71.
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Simplifique esta solución The Deep Dive
Let's substitute \( x = 1 \) and \( y = -8 \) into the polynomial \( x^2 - y^2 + xy \). First, calculate each term: - \( x^2 = 1^2 = 1 \) - \( y^2 = (-8)^2 = 64 \) - \( xy = 1 \cdot (-8) = -8 \) Now plug these values into the polynomial: \[ 1 - 64 - 8 = 1 - 64 - 8 = 1 - 72 = -71 \] So, the evaluation of the polynomial when \( x = 1 \) and \( y = -8 \) is \( -71 \).
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