Let $$ f(x)=5 x+2 $$ and $$ g(x)=3 x^{2}+2 x $$ After simplifying, $$ (f \circ g)(x)=\square $$

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Simplify the expression by following steps:
- step0: Multiply the terms:
  $$f\left(gx\right)$$
- step1: Multiply the terms:
  $$fgx$$
Expand the expression $$ 5(3x^2 + 2x) + 2 $$
Simplify the expression by following steps:
- step0: Expand the expression:
  $$5\left(3x^{2}+2x\right)+2$$
- step1: Expand the expression:
  $$15x^{2}+10x+2$$
To find $$ (f \circ g)(x) $$, we need to substitute $$ g(x) $$ into $$ f(x) $$.

1. We have $$ f(x) = 5x + 2 $$ and $$ g(x) = 3x^2 + 2x $$.
2. Now, we substitute $$ g(x) $$ into $$ f(x) $$:
   $$
   f(g(x)) = f(3x^2 + 2x) = 5(3x^2 + 2x) + 2
   $$

3. Next, we simplify this expression:
   $$
   = 5 \cdot 3x^2 + 5 \cdot 2x + 2 = 15x^2 + 10x + 2
   $$

Thus, after simplifying, we have:
$$
(f \circ g)(x) = 15x^2 + 10x + 2
$$

So, the final answer is:
$$
(f \circ g)(x) = 15x^2 + 10x + 2
$$
$$ (f \circ g)(x) = 15x^2 + 10x + 2 $$

Let \( f(x)=5 x+2 \) and \( g(x)=3 x^{2}+2 x \) After simplifying, \( (f \circ g)(x)=\square \)

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