18. $$ \frac{65 \mathrm{~kg}}{1 \mathrm{~L}}=\frac{x \mathrm{~g}}{1 \mathrm{~cm}^{3}} $$

Question

UpStudy AI · Accepted Answer

We are given the equation

$$
\frac{65\,\mathrm{kg}}{1\,\mathrm{L}} = \frac{x\,\mathrm{g}}{1\,\mathrm{cm}^3}.
$$

First, we convert the units to be consistent.

1 liter is equivalent to $$1000\,\mathrm{cm}^3$$.

Also, $$65\,\mathrm{kg}$$ is the same as $$65 \times 1000 = 65000\,\mathrm{g}$$.

Now, the density in grams per cubic centimeter is

$$
\text{Density} = \frac{65000\,\mathrm{g}}{1000\,\mathrm{cm}^3} = 65\,\mathrm{\frac{g}{cm^3}}.
$$

Therefore, we have

$$
\frac{x\,\mathrm{g}}{1\,\mathrm{cm}^3} = 65\,\mathrm{\frac{g}{cm^3}},
$$

which implies

$$
x = 65.
$$
$$ x = 65 $$

18. \( \frac{65 \mathrm{~kg}}{1 \mathrm{~L}}=\frac{x \mathrm{~g}}{1 \mathrm{~cm}^{3}} \)