The three numbers of the combination for a lock are consecutive integers, and their sum is 99. Find the combination. smallest value largest value SUBMIT ANSWER

Let's denote the three consecutive integers as \( x \), \( x+1 \), and \( x+2 \). 1. **Set up the equation for their sum:** \[ x + (x + 1) + (x + 2) = 99 \] 2. **Combine like terms:** \[ 3x + 3 = 99 \] 3. **Subtract 3 from both sides:** \[ 3x = 96 \] 4. **Divide by 3:** \[ x = 32 \] Now we can find the three consecutive integers: - The smallest integer is \( x = 32 \). - The next integer is \( x + 1 = 33 \). - The largest integer is \( x + 2 = 34 \). Thus, the combination for the lock is: - Smallest value: \( 32 \) - Largest value: \( 34 \) Final answer: - Smallest value: 32 - Largest value: 34