Pregunta
\begin{tabular}{l} Perform the indicated calculation. \\ \( { }_{10} \mathrm{P}_{2} \) \\ \hline\end{tabular}
Ask by Pierce Vaughn. in the United States
Mar 06,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The value of \( { }_{10} \mathrm{P}_{2} \) is 90.
Solución
To calculate \( { }_{10} \mathrm{P}_{2} \), we use the formula for permutations, which is given by:
\[
_{n}P_{r} = \frac{n!}{(n-r)!}
\]
In this case, \( n = 10 \) and \( r = 2 \).
Now, we can substitute these values into the formula:
\[
_{10}P_{2} = \frac{10!}{(10-2)!} = \frac{10!}{8!}
\]
Next, we can simplify \( \frac{10!}{8!} \):
\[
\frac{10!}{8!} = \frac{10 \times 9 \times 8!}{8!} = 10 \times 9
\]
Now, we can calculate \( 10 \times 9 \):
\[
10 \times 9 = 90
\]
Thus, the value of \( { }_{10} \mathrm{P}_{2} \) is \( 90 \).
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Extra Insights
To perform the calculation of \( { }_{10} \mathrm{P}_{2} \), which represents the number of permutations of 10 items taken 2 at a time, we use the formula: \[ _{n}P_{r} = \frac{n!}{(n-r)!} \] For our case, \( n = 10 \) and \( r = 2 \): \[ _{10}P_{2} = \frac{10!}{(10-2)!} = \frac{10!}{8!} = \frac{10 \times 9 \times 8!}{8!} = 10 \times 9 = 90 \] So, \( { }_{10} \mathrm{P}_{2} = 90 \).

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