Identify the height of a triangle in which $$ b=12 \mathrm{~m} $$ and $$ \begin{array}{l}A=(18 x-6) \mathrm{m}^{2} . \ h=(1.5 x-2) \mathrm{m} \ h=(2 x-1) \mathrm{m} \ h=(3 x-1) \mathrm{m} \ h=(x-2) \mathrm{m}\end{array} $$

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UpStudy AI · Accepted Answer

Given the area formula for a triangle, we have

$$
A = \frac{1}{2}bh.
$$

Since the base is given as $$ b = 12 \, \text{m} $$, substitute to obtain

$$
A = \frac{1}{2}(12)h = 6h.
$$

The area is also given by

$$
A = 18x - 6.
$$

Setting the two expressions equal gives

$$
6h = 18x - 6.
$$

Solve for $$ h $$ by dividing both sides by 6:

$$
h = \frac{18x-6}{6} = 3x-1.
$$

Thus, the height of the triangle is

$$
h = (3x-1) \, \text{m}.
$$
The height of the triangle is $$ h = 3x - 1 $$ meters.

Identify the height of a triangle in which and

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