Решите неравенство \( \frac{-10}{(x-3)^{2}-5} \geq 0 \)

Solve the equation \( \frac{-10}{(x-3)^{2}-5} \geq 0 \). Solve the inequality by following steps: - step0: Solve the inequality by testing the values in the interval: \(\frac{-10}{\left(x-3\right)^{2}-5}\geq 0\) - step1: Find the domain: \(\frac{-10}{\left(x-3\right)^{2}-5}\geq 0,x \in \left(-\infty,-\sqrt{5}+3\right)\cup \left(-\sqrt{5}+3,\sqrt{5}+3\right)\cup \left(\sqrt{5}+3,+\infty\right)\) - step2: Simplify: \(-\frac{10}{x^{2}-6x+4}\geq 0\) - step3: Change the sign: \(\frac{10}{x^{2}-6x+4}\leq 0\) - step4: Set the denominator of \(\frac{10}{x^{2}-6x+4}\) equal to 0\(:\) \(\begin{align}&x=\sqrt{5}+3\\&x=-\sqrt{5}+3\end{align}\) - step5: Determine the test intervals: \(\begin{align}&x<-\sqrt{5}+3\\&-\sqrt{5}+3\sqrt{5}+3\end{align}\) - step6: Choose a value: \(\begin{align}&x_{1}=0\\&x_{2}=3\\&x_{3}=6\end{align}\) - step7: Test the chosen value: \(\begin{align}&x<-\sqrt{5}+3\textrm{ }\textrm{is not a solution}\\&-\sqrt{5}+3\sqrt{5}+3\textrm{ }\textrm{is not a solution}\end{align}\) - step8: Include the critical value: \(\begin{align}&-\sqrt{5}+3