Find the solution of the system of equations. \[ \begin{array}{r}-x-7 y=-41 \\ \qquad x-6 y=-37\end{array} \] Answer Attempt 1 out of 2
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Let's solve the system step-by-step! First, we start with the two equations: 1. \( -x - 7y = -41 \) 2. \( x - 6y = -37 \) From equation 1, we can solve for \( x \): \[ -x = -41 + 7y \] \[ x = 41 - 7y \] Now we can substitute this expression for \( x \) into equation 2: \[ (41 - 7y) - 6y = -37 \] Combine like terms: \[ 41 - 13y = -37 \] Now, isolate \( y \): \[ -13y = -37 - 41 \] \[ -13y = -78 \] \[ y = 6 \] Now, substitute \( y \) back into either equation to find \( x \). Let's use equation 2: \[ x - 6(6) = -37 \] \[ x - 36 = -37 \] \[ x = -1 \] So, the solution to the system is \( x = -1 \) and \( y = 6 \). Therefore, the solution is \( (-1, 6) \).
