Pregunta
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Give an expression or formula for the number of squares \( (s) \) in the \( n \)th picture. INSTRUCTIONS: - The first part of the formula has been written for you. You must complete the formula in terms of \( n \). - You do not need to simplify the expression.

Ask by Best Jimenez. in South Africa
Mar 13,2025

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The number of squares \( s \) in the \( n \)th picture is \[ s = 1 + 2n(n - 1). \]

Solución

1. Recognize that in the first picture there is \( 1 \) square. 2. In each subsequent picture, additional squares are added. The pattern given is that the number of squares added at step \( k \) (for \( k = 1,\, 2,\, \dots,\, n-1 \)) is \( 4k \). 3. Therefore, the total number of squares \( s \) in the \( n \)th picture can be written as \[ s = 1 + \sum_{k=1}^{n-1} 4k. \] 4. Since the sum of the first \( n-1 \) positive integers is \[ \sum_{k=1}^{n-1} k = \frac{n(n-1)}{2}, \] we substitute to get \[ s = 1 + 4\left(\frac{n(n-1)}{2}\right). \] This is the required expression for the number of squares in the \( n \)th picture.

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Bonus Knowledge

To find the number of squares \( s \) in the \( n \)th picture, we can observe the pattern of squares being added as \( n \) increases. The initial part of the formula typically is \( s = n^2 + \) … where we recognize that each \( n \)th picture is creating a new square layer containing \( n \) squares on each side. Therefore, the completed expression could look like: \[ s = n^2 + (n-1)^2 + (n-2)^2 + \ldots + 1^2 \] This gives the total number of squares by summing the squares of consecutive numbers that fit within the structure defined by \( n \).

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