Pregunta
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Mmisi borrows an amount of money from Aggie. After two years, Mmasi pays back the money, plus \( 18 \% \) simple interest per year. He has to pay back an amount of R4080. How moch moncy did he borrow from Aggie? Nelis invests R 3000 for 5 years. He ends up with R4500. What was the simple interest rate? Ettiene wants to lonow for how long he needs to invest his R2 000 at \( 15 \% \) p-a. simple interest in order to have RI1 000. Answer Ertiene's question. Jurgen wants to buy a tumblo dryer for R1 500 . He cannot afford to pay all at once, so he buys it on hire purchasc. According to the agreement, he will pay back the money, plus \( 12 \% \) simple interest per year, by means of monthly payments, over a two-year period. (1) Calculate the total amount of money he'Il have to pay. (7) Caleulate hie menthis narvment

Ask by Barber Mcguire. in South Africa
Feb 09,2025

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Mmisi borrowed R3000. Nelis’ simple interest rate was 10% per annum. Ettiene must invest for 30 years. Jurgen’s total amount payable is R1860, and his monthly installment is R77.50.

Solución

We will solve each part in turn. ───────────────────────────── 1. Mmisi’s Loan Mmisi borrows an unknown sum (P) and, after 2 years at 18% simple interest per year, repays R4080. With simple interest the total amount is   Total = P + (P × rate × time)       = P + (P × 0.18 × 2)       = P + 0.36P       = 1.36P We have:   1.36P = 4080 Solve for P:   P = 4080 ÷ 1.36 = 3000 Thus, Mmisi initially borrowed R3000. ───────────────────────────── 2. Nelis’ Investment Nelis invests R3000 for 5 years and ends up with R4500. The accrued interest is   Interest = 4500 − 3000 = 1500 For simple interest the formula is   Interest = Principal × rate × time Thus,   1500 = 3000 × r × 5 Solve for r:   r = 1500 ÷ (3000 × 5)     = 1500 ÷ 15000     = 0.10 So the simple interest rate is 10% per annum. ───────────────────────────── 3. Ettiene’s Investment Ettiene wants to invest R2000 at 15% per annum simple interest and have a total of R11 000. (Note: The problem states “RI1 000”, and by the context and the size of the other amounts it is most reasonable to assume the intended amount is R11 000.) First, determine the total interest required:   Required interest = 11,000 − 2000 = 9000 Each year at 15% on R2000 earns:   Annual interest = 2000 × 0.15 = 300 Now, let t be the number of years needed:   300 × t = 9000 Solve for t:   t = 9000 ÷ 300 = 30 So, Ettiene must invest his money for 30 years. ───────────────────────────── 4. Jurgen’s Tumble Dryer on Hire Purchase Jurgen buys a tumble dryer priced at R1500 on hire purchase with simple interest at 12% per annum over 2 years. (i) Total Amount to Pay Calculate the simple interest over 2 years:   Interest = Principal × rate × time        = 1500 × 0.12 × 2        = 1500 × 0.24 = 360 Thus, the total amount payable is:   Total = Principal + Interest = 1500 + 360 = 1860 (ii) Monthly Installment There are 2 years of monthly payments, which means:   Number of months = 2 × 12 = 24 Monthly installment = Total amount ÷ number of months   = 1860 ÷ 24   = 77.5 Thus, he will pay R77.50 per month. ───────────────────────────── Summary of Answers 1. Mmisi borrowed R3000. 2. Nelis’ simple interest rate was 10% per annum. 3. Ettiene must invest for 30 years. 4. Jurgen’s total amount payable is R1860, and his monthly installment is R77.50.

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Beyond the Answer

To find out how much Mmasi borrowed, we can use the formula for simple interest: \( A = P(1 + rt) \). Here, \( A \) is the total amount repayable (R4080), \( P \) is the principal amount borrowed, \( r \) is the rate of interest (0.18), and \( t \) is the time in years (2). Rearranging the formula gives us \( P = \frac{A}{(1 + rt)} = \frac{4080}{(1 + 0.18 \times 2)} = \frac{4080}{1.36} = R3000 \). For Nelis's investment, we can again use the simple interest formula, rearranging it to find the interest rate. We know the initial amount (R3000), the final amount (R4500), and the time (5 years). The total interest earned can be calculated as \( 4500 - 3000 = R1500 \). Using the formula \( I = P \times r \times t \), we get \( 1500 = 3000 \times r \times 5 \), leading to \( r = \frac{1500}{15000} = 0.1 \) or 10% per annum. Now, for Ettiene's investment, we need to determine how long he must invest R2000 at 15% p.a. to reach R11000. Using the formula \( A = P(1 + rt) \), we can rearrange it to find \( t \): \( 11000 = 2000(1 + 0.15t) \). Simplifying gives \( 5.5 = 1 + 0.15t \), so \( 0.15t = 4.5 \), and \( t = 30 \) years. Finally, for Jurgen's tumble dryer purchase, to calculate the total amount he will have to pay under the hire purchase agreement, we first find the interest using the simple interest formula. The principal is R1500, the rate is 12%, and the time is 2 years. Thus, \( I = 1500 \times 0.12 \times 2 = R360 \). Therefore, the total amount he will pay is \( 1500 + 360 = R1860 \). To find his monthly payment, we need to divide this total by the number of months in two years (24 months): \( 1860 ÷ 24 = R77.50 \) per month.

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