Find the exact value of the expressi \( \tan \left(\arccos \left(\frac{\sqrt{3}}{2}\right)\right)=\square \) (Type an exact answer, using \( \pi \) and
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Bonus Knowledge
To find the exact value of \( \tan \left(\arccos \left(\frac{\sqrt{3}}{2}\right)\right) \), first determine the angle whose cosine is \( \frac{\sqrt{3}}{2} \). This angle is \( \frac{\pi}{6} \) or \( 30^\circ \). Now we calculate the tangent of this angle: \[ \tan\left(\frac{\pi}{6}\right) = \frac{\sin\left(\frac{\pi}{6}\right)}{\cos\left(\frac{\pi}{6}\right)} = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}}. \] So, the exact value of \( \tan \left(\arccos \left(\frac{\sqrt{3}}{2}\right)\right) \) is \( \frac{1}{\sqrt{3}} \). Final answer: \[ \tan \left(\arccos \left(\frac{\sqrt{3}}{2}\right)\right) = \frac{1}{\sqrt{3}}. \]
