\( f \log _{4} x=2 \), then \( x \) A) 8

To solve the equation \( f \log_{4} x = 2 \), we first isolate \( \log_{4} x \), which gives us \( \log_{4} x = \frac{2}{f} \). Changing it into exponential form, we have \( x = 4^{\frac{2}{f}} \). If we assume a specific value for \( f \), let’s say \( f = 1 \), then \( x = 4^2 = 16\). However, for \( f = 1/2 \), then \( x = 4^4 = 256\). So, without knowing \( f \), we can only express \( x \) in terms of \( f \). Let's explore different values of \( f \) further! If \( f = 2 \), then you’d find \( x = 4^{1} = 4\). It’s like a treasure hunt through logarithmic identities and bases—bring your calculator, and let’s unravel this mysterious \( x \)!