j) \( \frac{\left(x y z^{2}\right)^{-1}}{x^{2} y^{-1} z^{3}} \div\left(\frac{x^{3} y^{2} z^{0}}{x^{4} y^{2} z^{-3}}\right)^{-1} \times \frac{x y^{2} z^{4}}{x^{-3} y^{2} z^{0}} \)
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Bonus Knowledge
To simplify the expression, we will handle each part step by step. First, let's simplify the fraction: 1. For \( \frac{\left(x y z^{2}\right)^{-1}}{x^{2} y^{-1} z^{3}} \): - The numerator becomes \( \frac{1}{xyz^2} \). - Thus, we have \( \frac{1}{xyz^2} \div (x^2 y^{-1} z^3) = \frac{1}{xyz^2} \times \frac{1}{x^2 y^{-1} z^3} = \frac{y z^{-3}}{x^3 z^2} = \frac{y}{x^3 z^5} \). 2. Next, simplify \( \left(\frac{x^{3} y^{2} z^{0}}{x^{4} y^{2} z^{-3}}\right)^{-1} \): - This simplifies to \( (x^{-1} z^{3}) \) when simplified, as \( z^0 = 1 \) cancels out \( z^{-3} \) in the denominator after simplification. 3. Therefore, we find it becomes \( z^{3} / x \). Now, we can multiply it with the next term \( \frac{x y^{2} z^{4}}{x^{-3} y^{2} z^{0}} \): - Noticing \( z^{0} = 1 \), this turns into \( \frac{x y^{2} z^{4}}{x^{-3} y^{2}} = x^{4} z^{4} \). Putting all this together, the original expression is now: \[ \frac{y}{x^3 z^5} \cdot \frac{z^{3}}{x} \cdot (x^{4} z^{4}) \] This simplifies to \( \frac{y z^2}{x^6} \). Final simplified expression: \[ \frac{y z^{2}}{x^{6}} \]
