\( X ! + X ! + X ! = 360 \)

Let's simplify the equation \( X! + X! + X! = 360 \). Since there are three \( X! \) terms, we can combine them: \[ 3X! = 360 \] Now, divide both sides by 3: \[ X! = \frac{360}{3} = 120 \] Now we need to find \( X \) such that \( X! = 120 \). We can check the factorials of natural numbers: - \( 1! = 1 \) - \( 2! = 2 \) - \( 3! = 6 \) - \( 4! = 24 \) - \( 5! = 120 \) Thus, \( X = 5 \) is the solution since \( 5! = 120 \). So the final answer is \( X = 5 \).