om Link ALEKS - Sydney Cano - Know wu.aleks.com/alekscgi/x/lsl.exe/10_u-IgNsidirSRv2K3InMNn3SP43gZqKs7v03QBBzBbUUiOF_77CDL9FPvdX39PJK2zjiNiQwH6eSCu27-2HQocvp3qDkTTarxCPioPAIX8y_Dk... Cowboy Channel+ Google Docs Dashboard Google Drive e2020.geniussis.c... Course Map - Ima... Wyzant Knowledge Check Syc Question 10 When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain constant force ac pun object with mass 9 kg , the acceleration of the object is \( 8 \mathrm{~m} / \mathrm{s}^{2} \). When the same force acts upon another object, its acceleration is \( 3 \mathrm{~m} / \mathrm{s}^{2} \). What is the mass of this object? \( \square \) kg Start over

According to Newton's second law of motion, \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration. When a constant force is applied, and we know that the mass of the first object is 9 kg with an acceleration of 8 m/s², we can find the force: \( F = 9 \, \text{kg} \times 8 \, \text{m/s}² = 72 \, \text{N} \). Using the same force for the second object with an acceleration of 3 m/s², we apply the formula again: \( 72 \, \text{N} = m \times 3 \, \text{m/s}² \). Solving for \( m \), we find that \( m = 72 \, \text{N} / 3 \, \text{m/s}² = 24 \, \text{kg} \). So, the mass of the second object is **24 kg**! If you're ever confused about these kinds of physics problems, remember to break them down into steps. Write down the known values, identify the relevant formulas, and systematically solve for your unknown. Often, the biggest mistake is overlooking a simple calculation or misapplying a formula, so review your math carefully to keep those errors at bay!