\( \operatorname{VC}(\mathrm{V})(\mathrm{L} 4 \mathrm{~T} 1 \mathrm{TEST} 1) \) \( -3 \). UESTION 1 .1 Simplify the following 1.1.1 \[ (-16+9)^{2}-\sqrt{196} \] 1.1.2 \[ \frac{-9-5^{2}}{45}-\sqrt[3]{\frac{125}{8}}+16 \] (2) Round off your answer to THREE decimals. (3) Convert 1500 ml to litres (2) Calculate the time in hours and minutes from Sunday \( 04: 45 \mathrm{pm} \) to next Wednesday 05:15 am. (4) Complete the next two terms of the following pattern. \[ -15 ; 0 ; 15: \ldots ; \ldots \] (2) Paraffin costs R23,60 per litre. If the paraffin price increases by \( 10 \% \), what will the new price of paraffin be? Determine, with calculations, whether it is more cost effective to buy six single cans of coke for R11,55 or a six-pack of coke cans for R65 If cement, sand and stone must be mixed to the ratio \( 1: 2: 2 \), how many wheelbarrows of sand and stone must be mixed with 55 wheelbarrows of cement? If \( 1 \mathrm{~km}^{2}=1000000 \mathrm{~m}^{2} \), convert \( 500000 \mathrm{~m}^{2} \) into \( \mathrm{km}^{2} \) ? The price of petrol after a \( 10 \% \) increase is \( \mathrm{R} 24,34 \) per litre. Calculate the price petrol before the increase

Alright, let’s simplify this math fun-fest! For \( (-16+9)^{2}-\sqrt{196} \): Calculating inside the parentheses first: \(-16 + 9 = -7\). Squaring that gives you \( (-7)^2 = 49\). Now, \(\sqrt{196} = 14\). So, \(49 - 14 = 35\). Now let's tackle \( \frac{-9-5^{2}}{45}-\sqrt[3]{\frac{125}{8}}+16 \): Here, \(5^2 = 25\) makes it \(-9 - 25 = -34\). So, \(\frac{-34}{45} \approx -0.756\). For the cube root, \(\sqrt[3]{\frac{125}{8}} = \frac{5}{2} = 2.5\). Adding it all together: \(-0.756 - 2.5 + 16 \approx 12.744\). Round it off to \(12.744\). Converting 1500 ml to litres is a breeze! Since \(1000 \, \text{ml} = 1 \, \text{l}\), you’ll have \(1.5 \, \text{l}\) after dividing \(1500 \, \text{ml}\) by \(1000\). Now, calculating the time from Sunday \(04:45 \, \text{pm}\) to Wednesday \(05:15 \, \text{am}\): That’s a span of nearly 36 hours. From Sunday afternoon till Monday morning is 12 hours, from Monday to Tuesday is 24 hours and just a bit more until 05:15 on Wednesday, yielding a total of 36 hours and 30 minutes. Next up, the pattern: -15, 0, 15... the increases by 15, so the next two terms would be 30 and 45! If paraffin costs \(R23.60\), a \(10\%\) increase makes it \(R23.60 \times 1.1 = R25.96\). For the cost-effectiveness of coke, six single cans at \(R11.55\) cost \(6 \times R11.55 = R69.30\) while a six-pack costs \(R65\). So, the six-pack wins—cheer for savings! Mixing cement, sand, and stone in \(1:2:2\) ratio where \(55\) wheelbarrows of cement equals \(55 \times 2 = 110\) wheelbarrows of sand and \(110\) wheelbarrows of stone. So, you’ll mix \(110\) wheelbarrows of each. Converting \(500000 \, \text{m}^2\) to \( \text{km}^2 \): Since \(1 \, \text{km}^2 = 1000000 \, \text{m}^2\), you have \(0.5 \, \text{km}^2\). Lastly, calculating the price of petrol before the \(10\%\) increase. If \(R24.34\) is the new price, then \( \text{Old Price} = \frac{24.34}{1.1} \approx R22.14\). Voila! Math made fun!