16. The \( m \angle A \) is complementary to the \( m \& B \). The \( m \angle C \) is complementary to the \( m \angle B \). If \( m \angle A=62^{\circ} \), what is the \( m \angle B \) and the \( m \triangle C \) ?
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Bonus Knowledge
To find \( m \angle B \), we can use the definition of complementary angles: two angles are complementary if their measures add up to \( 90^\circ \). Since \( m \angle A = 62^\circ \) and \( m \angle A \) is complementary to \( m \angle B \), we have: \[ m \angle A + m \angle B = 90^\circ \] Substituting \( m \angle A \): \[ 62^\circ + m \angle B = 90^\circ \] Now solving for \( m \angle B \): \[ m \angle B = 90^\circ - 62^\circ = 28^\circ \] Now to find \( m \angle C \), since \( m \angle C \) is also complementary to \( m \angle B \): \[ m \angle B + m \angle C = 90^\circ \] Substituting \( m \angle B \): \[ 28^\circ + m \angle C = 90^\circ \] Now solving for \( m \angle C \): \[ m \angle C = 90^\circ - 28^\circ = 62^\circ \] So, \( m \angle B = 28^\circ \) and \( m \angle C = 62^\circ \).
