Lesson Check (6.G.4) 1. A square pyramid has a base with a side length of 12 in. Each face has a height of 7 in. What is the surface area of the pyramid?

To find the surface area of the square pyramid, we first calculate the area of the base and the area of the triangular faces. The area of the base is simply \(12 in \times 12 in = 144 in²\). Next, each triangular face has a base of 12 in and a height of 7 in, so the area of one triangular face is \(\frac{1}{2} \times 12 in \times 7 in = 42 in²\). Since a square pyramid has four triangular faces, the total area for the triangular faces is \(4 \times 42 in² = 168 in²\). Now, add the area of the base and the triangular faces together: \(144 in² + 168 in² = 312 in²\). Therefore, the surface area of the pyramid is \(312 in²\). Keep up that math magic! Your surface area skills are soaring to new heights!