D) If \( f(x)=(x-2)^{2} \); find the following. \( \begin{array}{ll}\text { 1) } 4 f(1) \times 6 f(0)=\square & \text { 2) }-8 f(2)+3 f(4)= \\ \text { 3) }-7 f(7)+f(-8)= \\ \text { What is the value of } f(-3) \text {, if } f(x)=10 x^{2}+8 ? & \text { i) } \frac{-3 f(-1)}{f(3)} \\ \text { i) } 9 \text { if }-88 & \text { lii) } 96\end{array} \)
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Beyond the Answer
Let’s dive into these calculations step by step, sprinkling in some fun with the math magic! First, we need the function value for specific inputs. Given \( f(x) = (x-2)^2 \): 1) \( f(1) = (1-2)^2 = 1 \) and \( f(0) = (0-2)^2 = 4 \). Now calculate: \[ 4 f(1) \times 6 f(0) = 4 \times 1 \times 6 \times 4 = 96 \] 2) For \( f(2) = (2-2)^2 = 0 \) and \( f(4) = (4-2)^2 = 4 \): \[ -8 f(2) + 3 f(4) = -8 \times 0 + 3 \times 4 = 12 \] 3) Calculate \( f(7) = (7-2)^2 = 25 \) and \( f(-8) = (-8-2)^2 = 100 \): \[ -7 f(7) + f(-8) = -7 \times 25 + 100 = -175 + 100 = -75 \] Next, to find \( f(-3) \): \[ f(-3) = (-3-2)^2 = 25 \] For \( f(x) = 10x^2 + 8 \): To find \( f(-1) \) and \( f(3) \): \[ f(-1) = 10(-1)^2 + 8 = 18 \text { and } f(3) = 10(3)^2 + 8 = 98 \] So, \[ \frac{-3 f(-1)}{f(3)} = \frac{-3 \times 18}{98} = \frac{-54}{98} = \frac{-27}{49} \] Finally, here's what you've got: 1) \( 96 \) 2) \( 12 \) 3) \( -75 \) \( f(-3) = 25 \) \( \frac{-27}{49} \)
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