Pregunta
Determine the horizontal asymptote of the graph of the following function. \( h(x)=\frac{x^{2}-7}{5 x^{5}+3} \)
Ask by Vaughn Ortiz. in the United States
Mar 20,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The horizontal asymptote is \( y = 0 \).
Solución
**Step 1:** Identify the degrees of the numerator and denominator.
The numerator is \( x^2 - 7 \) which is of degree 2.
The denominator is \( 5x^5 + 3 \) which is of degree 5.
**Step 2:** Compare the degrees.
Since the degree of the numerator (2) is less than the degree of the denominator (5), the horizontal asymptote is determined by the fact that the function approaches zero as \( x \) approaches infinity or negative infinity.
**Step 3:** State the horizontal asymptote.
The horizontal asymptote of the function is
\[
y = 0.
\]
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Como
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The Deep Dive
When determining the horizontal asymptote of the function \( h(x)=\frac{x^{2}-7}{5 x^{5}+3} \), we look at the degrees of the polynomial in the numerator and the denominator. The degree of the numerator, which is \(2\), is less than the degree of the denominator, which is \(5\). In such cases, the horizontal asymptote is at \(y=0\), indicating that as \(x\) approaches infinity or negative infinity, the value of the function approaches zero. So, the horizontal asymptote of \( h(x) \) is \( y = 0 \).

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