Given \( h(x)=f^{\prime}(x) \) where \( f \) is a function defined for \( -2 \leq x \leq 4 \) 1561 1562 Explain why \( f \) has a local mimmum to the graph of \( f \)
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Bonus Knowledge
To find a local minimum of the function \( f \), we look at its derivative \( h(x) = f'(x) \). A local minimum occurs where the derivative changes from negative to positive. If, at a certain point \( c \) within the interval \([-2, 4]\), we find \( f'(c) = 0 \) and \( f'(x) \) is negative for \( x < c \) and positive for \( x > c \), then \( f \) has a local minimum at \( x = c \). This means that just before \( c \), the function is decreasing, and just after \( c \), it starts increasing, forming a "valley" in the graph. In addition, if \( h(x) \) has points of inflection or if there are values where \( h(x) \) becomes zero, it gives us a clue about the sharp turns in the function \( f \). If \( f'(x) \) has those zeroes in our interval, they will indicate potential local extrema (minimums or maximums) in conjunction with the first derivative test. Checking the endpoints is also crucial to verify if they yield lower values than the points found inside the interval.
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